This article was originally posted on my blog. Head over to inspiredwebdev.com for more articles and tutorials. Check out my JavaScript course on ...
For further actions, you may consider blocking this person and/or reporting abuse
Or this:
You can do a very similar thing with array methods and rest operator:
Yeah with RegEx you can do it very easily but I feel like it makes the code less readable.
You might find it's simpler if you rearrange it slightly. :)
Yep, that also works :)
Is it just me or does your RegEx not work? I mean what you have is this:
And it's basically saying does my word have at least one letter in it? So it if you have a semicolon attached to the end of your word, it will not be ignored. I think what you meant was someting like this:
That is if you wanted to ignore words with characters altogether.
Although what I thought when I read the task was that you were meant to rearrange the letters and keep the punctuation marks at the end, if any.
Uhm, I think what the task meant with
leave the punctuation marks untouched
was in the case of them being alone, so if you have!
you don't want to end up with!ay
. My solution would transformhello!
toello!hay
which may be wrong, you are right. They should have had stricter tests and a better description on CodeWars lol, they have no test case for a punctuation mark attached to a string.Great explanation, thanks.
Thanks, i'm happy you liked it
Please note .. this is not the complete rules for PigLatin ..
Have a look at scotch.io/courses/the-ultimate-gui...
Yes, i've taken it from CodeWars, that's why it's called 'Simple Pig Latin', it's a simpler version.
thank you i liked...
This is awesome! Keep 'em coming!
Thanks!, I will