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Dan Fletcher
Dan Fletcher

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Type Widening Is Kinda Weird

#typescript #webdev

Do you notice how in TypeScript that when you initialize a variable to a boolean, string or number, that TypeScript infers the type to be exactly that? A boolean, string or number.

For example:

let a = 4
a = 5
a // is 5 since type is number not 4
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💡 Keep in mind, if you use const it prefers the more specific type 4

This is a huge feature of TypeScript! Type Inference is essential to writing easy to read, and maintainable TS codebases. It removes a lot of verbosity as well as reduces the amount of type code that has to be updated when a type upstream changes.

However there are some times, where this can cause weird errors. For example, I didn’t guess at first glance that the below code would cause a type error:

type User = {
  kind: 'user'
  name: string
};

function userName(user: User) {
  return user.name;
}

const user = {
  kind: 'user',
  name: 'Jane',
};
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Can you spot the error?

If you caught it, great! If not, here's the issue you'll see from TypeScript:

Argument of type '{ kind: string; name: string; }' is not assignable to parameter of type 'User'.
  Types of property 'kind' are incompatible.
    Type 'string' is not assignable to type '"user"'.
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Essentially what's happening is kind gets widened to type string when creating the user object, but the function expects kind to be type 'user'.

Solution

So what's the solution?

Use as const:

const user = {
  kind: 'user' as const,
  name: 'Jane',
};
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When we use as const it tells TypeScript that we don't want the inference to prefer the wider type of string but instead use the more narrow type 'user'. And in this case, our error above goes away!

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Top comments (2)

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thediamondcg profile image
Diamond •

You are better off using something like

{
  kind: 'employee' | 'user',
  name: string
}
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or

{
  kind: string,
  name: string
}
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because it better communicates code intent. If I saw the User type as it was in your blog post, I'd be very confused as to why I'm seeing a field that can only ever be 'employee'.

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danjfletcher profile image
Dan Fletcher • • Edited

Oh you caught a typo! Let me fix that. It should be 'employee' or 'user' everywhere in these examples.

The example I was pulling from, instead of the union though, is like:

type Employee = {
  kind: 'employee',
  name: string
}

type Admin = {
  kind: 'admin',
  name: string
}

type User = Employee | Admin
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Where kind is the discriminator, if that makes sense

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