Mux is a powerful HTTP router that matches incoming requests against a list of registered routes and calls a handler for the route that matches the URL or other conditions.
Enough talking ....
Please create a new file called main.go and paste the below contents
package main
import (
"fmt"
"github.com/gorilla/mux"
"io"
"log"
"net/http"
"os"
)
func UploadFile(w http.ResponseWriter, r *http.Request) {
file, handler, err := r.FormFile("file")
fileName := r.FormValue("file_name")
if err != nil {
panic(err)
}
defer file.Close()
f, err := os.OpenFile(handler.Filename, os.O_WRONLY|os.O_CREATE, 0666)
if err != nil {
panic(err)
}
defer f.Close()
_, _ = io.WriteString(w, "File "+fileName+" Uploaded successfully")
_, _ = io.Copy(f, file)
}
func homeLink(w http.ResponseWriter, r *http.Request) {
_, _ = fmt.Fprintf(w, "Welcome home!")
}
func main() {
router := mux.NewRouter().StrictSlash(true)
router.HandleFunc("/", homeLink)
router.HandleFunc("/file", UploadFile).Methods("POST")
log.Fatal(http.ListenAndServe(":8081", router))
}
Build it - go build
Run it - go run main.go
Test it - Using Postman/Curl
Postman:
CURL:
curl -X POST \
http://localhost:8081/file \
-H 'Accept: */*' \
-H 'Accept-Encoding: gzip, deflate' \
-H 'Cache-Control: no-cache' \
-H 'Connection: keep-alive' \
-H 'Content-Length: 4251' \
-H 'Content-Type: multipart/form-data; boundary=--------------------------489143350034706567613009' \
-H 'Host: localhost:8081' \
-H 'Postman-Token: fea94e80-8294-4f0b-87bf-09b706eddac8,1bbb735b-f88d-4194-a1b5-f8cd90189545' \
-H 'User-Agent: PostmanRuntime/7.17.1' \
-H 'cache-control: no-cache' \
-H 'content-type: multipart/form-data; boundary=----WebKitFormBoundary7MA4YWxkTrZu0gW' \
-F file=@/Users/vasubabujinagam/Documents/protobuf-3.9.2/CONTRIBUTORS.txt \
-F file_name=file1
Top comments (1)
Hii thanks for the article its really helpfull. But i got error when trying to upload the f which is file the copyied from file at line _, _ := io.Copy(f, file).
So the problem when i upload f cloudinary using this
uploadResult, err := cld.Upload.Upload(ctx, f, uploader.UploadParams{})
err return access denied, i also had trying to change permision at .OpenFile() from 0666 to 0777 but its still the same