setTimeout(() => console.log('1'), 0);
Promise.resolve().then(() => console.log('2'));
console.log('3');
Thanks for reading π
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Top comments (2)
That's going to be
3, 2, 1. Why:Start execution. Put
setTimeout's callback into the task queue. Since a promise is already resolved, putthen's callback into the microtask queue. Executeconsole.log('3');. Then we execute the microtask(then's callback) and itsconsole.log(2);because microtasks are executed before regular tasks whenever the call stack empties. Then the task(setTimeout's callback) executed andconsole.log(1);in it.Awesome π₯π