How to connect Ipython with own frontend?

#python #ipython #jupyter #opensource

I am a college student working on a project to create a Python playground website where users can write and run Python code. I am using the Ace code editor for the frontend, and I believe I need to use IPython in the backend to provide a Python environment for users to execute their code.

However, I am unsure about how to proceed with integrating IPython into my website. Specifically, I need guidance on how to communicate with the IPython kernel and frontend. Additionally, I would like to set up isolated environments for each user using Docker, but I'm not sure how to implement this.

Also, I think the Jupyter client can be an easy way to communicate with Kernal.

Top comments (4)

Mohsin • Mar 15

You can leverage a running IPython kernel and connect your frontend to it

SHRAY SALVI • Mar 16

Here is my client.py file which I am going to use to connect with a kernel

from jupyter_client import KernelManager

def main():
    # Create a new kernel manager
    km = KernelManager(kernel_id='9912')
    km.start_kernel()

    # Create a client to interact with the kernel
    kc = km.client()
    kc.start_channels()

    # Ensure the client is connected before executing code
    kc.wait_for_ready()

    # Execute the code
    code = 'print("Hello, World!")'
    msg_id = kc.execute(code)

    # Wait for the result and display it
    while True:
        try:
            msg = kc.get_iopub_msg(timeout=1)
            print(msg)
            content = msg["content"]

            # When a message with the text stream comes and it's the result of our execution
            if msg["msg_type"] == "stream" and content["name"] == "stdout":
                print(content["text"])
                break
        except KeyboardInterrupt:
            print("Interrupted by user.")
            break
        except:
            # If no messages are available, we'll end up here, but we can just continue and try again.
            pass

    # Cleanup
    kc.stop_channels()
    km.shutdown_kernel()

if __name__ == '__main__':
    main()

Now I am confused about whether KernelManager(kernel_id='9912') is connecting to my configured kernel or create one on its own.

Here is my complete process -

Step 1

Created a k_conf.json file to configure kernel

{
    "shell_port": 63101,
    "iopub_port": 63102,
    "stdin_port": 63103,
    "control_port": 63106,
    "hb_port": 63105,
    "ip": "127.0.0.1"
  }

Then I used the command ipython kernel k_conf.json
Output:

NOTE: When using the `ipython kernel` entry point, Ctrl-C will not work.

To exit, you will have to explicitly quit this process, by either sending
"quit" from a client, or using Ctrl-\ in UNIX-like environments.

To read more about this, see https://github.com/ipython/ipython/issues/2049

To connect another client to this kernel, use:
    --existing kernel-9912.json

TO check the output is basically generated from the kernel with k_conf.json configuration or not I need the log of created kernel.

SHRAY SALVI • Mar 16

I think it is creating a new kernel, as it created a new file in my tmp/ directory, kernel-9912.json

SHRAY SALVI • Mar 16

I can simply run the ipython kernel with the help of ipython kernel and Now I wanted to connect to that kernel and I believe jupyter_client would be beneficial in this case but I am unable to connect to the kernel.

DEV Community

How to connect Ipython with own frontend?

Top comments (4)

Step 1

Read next

Sort Items in a Directory by Descending Size Using Python, PowerShell, C#, or Go

LangGraph State Machines: Managing Complex Agent Task Flows in Production

A Comparative Analysis between RK3588 and RK3576 Chips: Unveiling the Technological Distinctions

BCEWithLogitsLoss in PyTorch