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Daily Challenge #15 - Stop gninnipS My sdroW!

dev.to staff on July 15, 2019

Good morning, everyone. Let's warm up for the start of the week by playing with strings. s'yadoT egnellahc semoc from user xDranik on sraWedoC! ...

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willsmart • Jul 15 '19 • Edited

JS quickie

theString => theString.split(' ').map(
  word => word.length >= 5 ?
    [...word].reverse().join('')
    : word
).join(' ')

Yozen Hernandez • Jul 15 '19

Perl one-liner:

my $string = "Good luck, Happy coding!"; my $res = join " ", map { (length($_) >= 5) ? scalar reverse($_) : $_ } split / /, $string; say $res;

A bit more cleaned up, taking user input:

#!/usr/bin/perl

use v5.24;
use strict;
use warnings;
use Carp;

# Challenge says only letters and spaces, but this won't be picky
sub reverse_over_4 {
    my $string = shift or croak "Error: missing argument to function.";
    my $res    = join " ",
        map { ( length($_) > 4 ) ? scalar reverse($_) : $_ } split / /,
        $string;
    return $res;
}

print "Enter string: ";
my $input = <STDIN>;
chomp $input;
say reverse_over_4($input);

See runnable demo on PerlBanjo

E. Choroba • Jul 16 '19

Note that ($_) is not needed for length and reverse.

Yozen Hernandez • Jul 16 '19

Yeah, true, that's just my personal preference 🙂

willsmart • Jul 15 '19 • Edited

And one that modifies a string inplace using C

#include <stdio.h>
#include <string.h>

char *unspin(char *input) {
    for (
        char *eoinput = input + strlen(input),
             *nextSpace=input,
             *nextWord=input ;

        nextSpace < eoinput ;

        nextWord = nextSpace + 1 ,
        nextSpace = memchr(nextWord,' ',eoinput-nextWord),
        nextSpace = nextSpace ? nextSpace : eoinput
      ) {
        if (nextSpace >= nextWord + 5) for (
            char *wordStart = nextWord, 
            *wordEnd = nextSpace-1 ;

            wordStart < wordEnd ;

            ++wordStart,
            --wordEnd
        ) {
            *wordStart += *wordEnd;
            *wordEnd = *wordStart - *wordEnd;
            *wordStart -= *wordEnd;
        }
      }
      return input;
}

int main()
{
    char s[] = "Stop gninnipS My sdroW";
    printf("%s", unspin(s));

    return 0;
}

Alvaro Montoro • Jul 15 '19

JavaScript

const spinner = sentence => sentence.split(' ')
                                    .reduce((acc, val) => `${acc} ${val.length > 4 ? val.split('').reverse().join('') : val}`, '')
                                    .trim();

Using reduce to generate a string from the array, but then I have to use trim as I end up with a space at either end :-/

Live demo on CodePen.

willsmart • Jul 15 '19

Nice one!
If you replace the trim() with a substring(1) then it'll work with strings that have spaces in front and behind since you're reliably adding a single space to the front, none to the back.

See the warning here re thesplit('') call. Seems the recommended way now is [...string].

Kerri Shotts • Jul 16 '19

This one was fun! I decided to approach it from a slightly different angle by building a general-purpose when function that could be used to decide when to map to a value (vs return the original value) based on a condition... just for kicks :-)

Here's my go:

const when = (when = () => false, fn = i => i) => 
    (v, idx, arr) => when(v, idx, arr) 
        ? (typeof fn === "function" ? fn(v, idx, arr) : fn)
        : v;

const reverseString = str => Array.from(str).reverse().join("");

const reverseWords = ({inString = "", ofLength = 0} = {}) => 
    inString.split(" ")
        .map(when(w => w.length >= ofLength, reverseString))
        .join(" ");

const gnirtS = reverseWords({inString: "one two three four", ofLength: 5});

Gist (w/ some tests): gist.github.com/kerrishotts/ac0f30...

Anmol Gautam • Jul 16 '19 • Edited

Haskell, with user input

condRev :: [Char] -> [Char]
condRev s = if length s >= 5 then reverse s else s

toString :: [[Char]] -> [Char]
toString [] = []
toString (x:[]) = x
toString (x:xs) = x ++ " " ++ toString xs

solve :: [Char] -> IO ()
solve s = putStrLn $ toString $ map condRev $ words s

main :: IO ()
main = do
    line <- getLine
    solve line

Aadi Bajpai • Jul 16 '19 • Edited

Python one-liner:
for x in input().split(): print(x[::1]*(len(x)<5) or x[::-1], end=' ')

65 chars at most :)

Or,
print(*map(lambda x: x[::1]*(len(x)<5)or x[::-1], input().split()))

Also 65 at most :)

Corey Alexander • Jul 15 '19

Here is my Rust solution and test cases!

The Rust std lib made this one pretty simple!

pub fn spin_words(input: &str) -> String {
    input
        .split(" ")
        .map(|word| {
            if word.len() >= 5 {
                word.chars().rev().collect()
            } else {
                word.to_string()
            }
        })
        .collect::<Vec<String>>()
        .join(" ")
}

#[cfg(test)]
mod tests {
    use crate::*;

    #[test]
    fn it_works_for_words_shorter_than_4_chars() {
        assert_eq!(spin_words("Test"), "Test".to_string());
        assert_eq!(spin_words("Te"), "Te".to_string());
        assert_eq!(spin_words("ant"), "ant".to_string());
        assert_eq!(
            spin_words("lots of tiny word"),
            "lots of tiny word".to_string()
        );
    }

    #[test]
    fn it_words_for_the_example() {
        assert_eq!(
            spin_words("Stop gninnipS My sdroW"),
            "Stop Spinning My Words".to_string()
        );
    }

    #[test]
    fn it_words_with_space_padded_strings() {
        assert_eq!(
            spin_words(" Stop gninnipS My sdroW "),
            " Stop Spinning My Words ".to_string()
        );
    }
}

Oleksii Filonenko • Jul 16 '19 • Edited

Elixir:

defmodule Spinner do
  @spec spin(String.t()) :: String.t()
  def spin(sentence) do
    String.replace(sentence, ~r/\w+/, fn word ->
      if String.length(word) > 4 do
        String.reverse(word)
      else
        word
      end
    end)
  end
end

"Please spin me around!"
|> Spinner.spin()
|> IO.puts()

# => "esaelP spin me dnuora!"

Praneet Nadkar • Jul 16 '19

A quick one in C#

 var input = Console.ReadLine().Split(' ');
 var output = new List<string>();
 foreach (var word in input)
 {
    if (word.Length <= 4)
    {
      output.Add(word);
      continue;
    }

    // word reversal. This can be done using inbuilt functions as well
    var wordArray = word.ToCharArray();
    var current = string.Empty;
    for (int i = word.Length - 1; i >= 0 ; i--)
    {
       current += wordArray[i];
    }

    output.Add(current);
 }

 Console.WriteLine(string.Join(" ", output));
 Console.ReadKey();

Mihail Malo • Jul 16 '19 • Edited

Rust, sort of in place

fn reverse_in_place(input: &mut [u8]) {
    input
        .split_mut(|&byte| byte == b' ')
        .filter(|word| word.len() >= 5)
        .for_each(<[_]>::reverse);
}

The rest of the story below the fold:

fn reverse(input: &str) -> String {
    let mut output = input.as_bytes().to_vec();
    reverse_in_place(&mut output);
    String::from_utf8(output).unwrap()
}

fn main() {
    let test = "Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!";
    println!("{}", reverse(test));
    println!("{}", reverse(&reverse(test)));
}

Payton Bice • Jul 17 '19 • Edited

PHP 5.3.0 to 7.3.x:

preg_replace_callback('/(\b\w{5,}\b)+/i', function ($match) {
    return strrev($match[0]);
}, 'Hello world, this is a test string.');

PHP >= 7.4:

preg_replace_callback('/(\b\w{5,}\b)+/i', fn($match) => strrev($match[0]), 'Hello world, this is a test string.');

Shannon Crabill • Sep 27 '19

Ruby

def wordSpinner(string)
  string.split(" ").map do |word|
    if word.length >= 5
      word.reverse
    else
      word
    end
  end.join(" ")
end

Tests

wordSpinner("Everything small is just a smaller version of something big")
wordSpinner("Bad biscuits make the baker broke bro")
wordSpinner("Sometimes life is scary and dark")

Results

"gnihtyrevE llams is just a rellams noisrev of gnihtemos big"
"Bad stiucsib make the rekab ekorb bro" 
"semitemoS life is yracs and dark"

Mikhail Korolev • Jul 16 '19 • Edited

Ruby

string.split.map{ |s| s.length >= 5 ? s.reverse! : s } * " "

K.V.Harish • Oct 16 '19

My solution in js

const reverseWords = sentence => sentence.split(' ')
                                         .map(word => word.length > 4 ? word.split('').reverse().join('') : word)
                                         .join(' ');

Oryan Moshe • Jul 15 '19

const spinner = sentence =>
  sentence.split(' ')
    .map(word =>
      word.length > 4 ?
        word.split('').reverse().join('') :
        word
      )
    .join(' ')

Craig McIlwrath • Aug 20 '19

Haskell:

flipWords :: String -> String
flipWords = unwords . map (\w -> if length w > 4 then reverse w else w) . words

Chandra Shekhar • Jul 17 '19

Python 3 : :P

s='yadoT egnellahc semoc from user xDranik on sraWedoC!'
print(s[::-1])

Praveen Bisht • Jul 16 '19 • Edited

JS/ES

const revWords = str => {
    return str
        .split(" ")
        .map(word => (word.length >= 5 ? [...word].reverse().join("") : word))
        .join(" ")
};

Samarth Tripathi • Sep 8 '21

function spinWords(string){
return string.split(' ').map(function(string){
return (string.length > 4) ? string.split('').reverse().join('') : string
}).join(' ');
}