Seek and Destroy Algorithm

DESCRIPTION:

You will be provided with an initial array (the first argument in the destroyer function), followed by one or more arguments. Remove all elements from the initial array that are of the same value as these arguments.
hint : use arguments object


arguments object from W3schools

JavaScript functions have a built-in object called the arguments object.
The argument object contains an array of the arguments used when the function was called (invoked).
This way you can simply use a function to find (for instance) the highest value in a list of numbers:

Examples

destroyer(["tree", "hamburger", 53], "tree", 53)
// should return ["hamburger"].

destroyer([2, 3, 2, 3], 2, 3) 
// should return [].

My approach for solving this problem:

1- first read about arguments object (I think it's Ok to use google and learn new Thing I'm not an expert).

2- I need to sprite the arguments into 2 arrays,
one for parameter Arr and other for the rest Arguments.

3- filter the Arr and return item if it's not includes into OtherArguments.

My solution:

function destroyer(arr) {
  let OtherArguments = Object.values(arguments).splice(1)

  return arr.filter(item=> !OtherArguments.includes(item))
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Other approach for solving this problem:

1- you don't need arguments object.

2- I need to sprite the arguments into 2 arrays,
one for parameter Arr and other for the rest Arguments.

3- we can use (...) rest parameter insted of Object.values.

4- filter the Arr and return item if it's not includes into OtherArguments.

Other solution:

function destroyer(arr,...OtherArguments) {

    return arr.filter(item=> !OtherArguments.includes(item))

}
destroyer([1, 2, 3, 1, 2, 3], 2, 3)

Any tips or edit are most welcome. share it with me on the comments. Thanks for being here!

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