1 line of code: How to reverse all words of a string

#javascript #webdev #productivity #codequality

const reverseWords = (str) =>  str.split(" ").map((word) => [...word].reverse().join("")).join("");

Returns the string with all words reversed

Improved version with unicode support

const reverseWords = (str) => str.replace(/(\p{L}+)/gu, (word) => [...word].reverse().join(''));

You can find the all the utility functions from this series at github.com/martinkr/onelinecode
The library is also published to npm as @onelinecode for your convenience.

The code and the npm package will be updated every time I publish a new article.

This would put the punctuation at the start of the last word, so let me suggest an improved version:

const reverseWords = (str) => str.replace(/\w+/g, (word) => [...word].reverse().join(''))

Hi Alex,

thank you for taking the time to improve the code.
I like your Idea and updated the article.

Cheers!

We could also use the new RegExp Extension for Unicode property classes and use /(\p{L}+)/gu as the RegExp.

Hey everyone,

thank you both for your thoughtull contribution.
After comparing the support tables for JavaScript built-in: Intl: Segmenter and JavaScript built-in: RegExp: unicode I perfer staying with the Regular Expression @lexlohr proposed.

I updated the script and the code as well as the testcases to inlcude unicode support.

Cheers!

const reverseWords = ([...str]) => str.reverse().join``.split` `.reverse().join` `