JavaScript methods are actions that can be performed on objects. So here is my new blog post I will cover the two JavaScript methods map() and filter(). Will explain easily and in detail.

map()

-> The map() method is used to apply a function on every element in an array and then return a new array.
Let's take a look at the syntax:-

let newArray = array.map( (v, i, a) => {
    // return element to newArray
});

// newArray - the new array that is returned
// array - the array to run the map function on
// v - the current value being processed
// i - the current index of the value being processed
// a - the original array

The map() method can be thought of as for loop, that is specifically for transforming values. Let's take a look at this example:

let nums = [11, 12, 13, 14];
let minus10 = [];
for(let i = 0; i < nums.length; i++) {
    minus10[i] = nums[i] - 10;
 }

The code results in a new array where each value of the old array is reduced by 10. Yes, it works, but there is an easier way to achieve the same result.

Now let's rewrite the previous function using the map() method.

let nums = [11, 12, 13, 14];
let minus10 = nums.map(value => value - 10);
  // minus10 = [1, 2, 3, 4]

Just see. Without any loop

And using the arrow function we have a nice and clean function to create the same array. Because we only use the value, we only pass that to the map() method.

Here in this example, we'll utilize both the value and index arguments.

let nums = [11, 12, 13, 14];
let newArray = nums.map( (v, i) => {
  return {
     value: v,
     index: i
   };
});

// newArr = [
// {value: 11, index: 0},
// {value: 12, index: 1},
// {value: 13, index: 2},
// {value: 14, index: 3}
//   ]

I think now you are seeing that whatever we return within the map() method is used to create the new array. You can use the current value, current index or even the entire array to determine what to return.

let nums = [11, 12, 13, 14]; 
let cats = nums.map ( ( ) => 'cats');
 // cats = [`cat`, `cat`, `cat`, `cat` ]

Till here, all the examples have transformed all of the values in the old array. Let's look at a way to transform some of the values in our array.

let nums = [11, 12, 13, 14]; 
ley newArr = nums.map(v => v % 2 === 0 ? v * 2 : v);
  // newArr = [11, 24, 13, 28];

First, we checked if the value divided by two has a remainder of zero. If the remainder is zero we'll return v * 2 or double the current value.