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Posted on Aug 14, 2019

Daily Challenge #40 - Counting Sheep

#challenge

You're having trouble falling asleep, so your challenge today is to count sheep!

Given a non-negative integer, 3 for example, return a string with a murmur: "1 sheep...2 sheep...3 sheep...". Input will always be valid, i.e. no negative integers.

Happy Coding!

This challenge comes from joshra on CodeWars. Thank you to CodeWars, who has licensed redistribution of this challenge under the 2-Clause BSD License!

Want to propose a challenge for a future post? Email yo+challenge@dev.to with your suggestions!

Top comments (34)

Henry 👨‍💻 • Aug 14 '19

This was quite a simple one so I decided to spice it up with emoji! Also, next-gen sleep simulation at the end.

Code:

# -*- coding: UTF-8 -*-

def countSheep(sheepToCount):
        sheepString = ""
        outputString = ""
        for i in range(sheepToCount):
                sheepString += "🐑 "
                outputString += "{}... ".format(sheepString)
        outputString +="ZZZzzzzzzz"
        print(outputString)

countSheep(5)

Output:

🐑 ... 🐑 🐑 ... 🐑 🐑 🐑 ... 🐑 🐑 🐑 🐑 ... 🐑 🐑 🐑 🐑 🐑 ... ZZZzzzzzzz

La blatte • Aug 14 '19

Did anybody talk about oneliner?

f=(i)=>[...Array(i)].map((_,i)=>`${i+1} sheep... `).join``

And the results

f(10);
// "1 sheep... 2 sheep... 3 sheep... 4 sheep... 5 sheep... 6 sheep... 7 sheep... 8 sheep... 9 sheep... 10 sheep... "

Andy Mardell • Aug 14 '19 • Edited

This is sweet. Something similar but with more Array and less map:

const f = i => Array.from(Array(i), (_, i) => `${i + 1} sheep... `).join``

const f = i => Array.from({ length: i }, (_, i) => `${i + 1} sheep... `).join``

Darryl Norris • Aug 14 '19

PHP

<?php

/**
 * Daily Challenge #40 - Counting Sheep
 *
 * @param  int    $number Number of sheeps.
 * @return string
 */
function countingSheep(int $number): string
{
  $text = '';
  for ($i = 1; $i <= $number; $i++) {
    $text .= "$i sheep...";
  }

  return $text;
}


echo countingSheep(3);
// Output: 1 sheep...2 sheep...3 sheep...

Daniel Santos • Aug 14 '19

JavaScript

function cs(n) {
    if (typeof n != "number" && n < 0) return `${n} is not a valid number`;

    let text = "";

    for(let x = 0; x < n; x++) {
        text += `${x} sheep... `
    }

    return text;
}

cs(3) // 0 sheep... 1 sheep... 2 sheep...

Donald Feury • Aug 15 '19

PHP

I counted bugs because that is more reflective of what I would do while working :)

I also added a message for if you are able to go to sleep immediately

<?php

function countBugs(int $bugs): string {
  if ($bugs === 0) {
    return "sleep tight..." . PHP_EOL;
  }

  $count = 0;
  $text = ++$count . " bug..." . PHP_EOL;

  while ($count < $bugs) {
    $text .= ++$count . " bugs.." . PHP_EOL;
  }

  return $text;
}

echo "Counting three bugs..." . PHP_EOL;
echo countBugs(3);

echo "Counting no bugs..." . PHP_EOL;
echo countBugs(0);

Seiei Miyagi • Aug 15 '19

ruby <3

def count_sheep(n)
  1..n |> map { "#@1 sheep..." } |> join
end

Josh • Aug 16 '19

Ruby has pipes now?

Seiei Miyagi • Aug 16 '19

Yes! pipeline operator added.

Feature #15799: pipeline operator - Ruby master - Ruby Issue Tracking System

And Numbered parameters.

Feature #4475: default variable name for parameter - Ruby master - Ruby Issue Tracking System

It's not released yet. You can try those new syntax by rbenv install 2.7.0-dev.

Seiei Miyagi • Sep 2 '19

Sadly, pipeline operator is reverted.
github.com/ruby/ruby/commit/2ed68d...

Darryl Norris • Aug 14 '19 • Edited

JavaScript

/**
 * Daily Challenge #40 - Counting Sheep
 *
 * @param  {number}        Number of sheeps.
 * @return {string}
 */
const countingSheep = number => {
  // Checking if positive integer or not.
  if (!(number >>> 0 === parseFloat(number))) {
    return `${number} is not a positive integer`;
  }

  let text = '';

  // Building text.
  for (let i = 1; i <= number; i++) {
    text += `${i} sheep...`;
  }
  return text;
};

console.log(countingSheep(3));
// Output: 1 sheep...2 sheep...3 sheep...

BHAVESH GUPTA • Aug 15 '19

Most of the solutions are not taking input
0
into consideration.
Like for 0 the output should be
"0"
not an empty string.

Edit that can be made to question statement.
As according to question input can be a non-negative number. For rest of the inputs it should be like for 3,
"0 1 sheep...2 sheep... 3sheep..."

Pattern is print the numbers upto n starting with 0 and concate the string " sheep..." with them.

Alvaro Montoro • Aug 15 '19

I kind of understand your suggestion (as zero is not positive nor negative, and the question statement would be more accurate if it was "Given a positive integer"), but I don't see why you suggest that base case.

Why for zero the output should be "0" and not "0 sheep..." or an empty string?

BHAVESH GUPTA • Aug 15 '19

I made some assumptions for the pattern.

As i think the pattern is to print the numbers upto inputted number and concatinating string " sheep...", so as the total number of string " sheep..." in output string is equal to inputted number. that is no string for 0 but the "0" represent the number.

Josh • Aug 16 '19 • Edited

Oh, alright.

shep = fn
  0 -> ""
  n -> 1..n |> Stream.map(&("#{&1} sheep")) |> Enum.join("...") 
end

IO.puts(shep.(0))
#

K.V.Harish • Oct 6 '19

My solution in js

const murmur = (times) => Array(times).fill()
                                      .map((value, index) => `${index+1} sheep...`)
                                      .join(' ');

Alvaro Montoro • Aug 15 '19

Scheme

(define (countSheep n)
  (if (< n 1) 
    ""
    (string-append (countSheep (- n 1)) (number->string n) " sheep...")
  )
)

A demo can be seen in Repl.it. The function would be called (countSheep 4) and the result would be:

"1 sheep...2 sheep...3 sheep...4 sheep..."

View full discussion (34 comments)

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Daily Challenge #40 - Counting Sheep

Top comments (34)

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