Given two numbers, hour
and minutes
, return the smaller angle (in degrees) formed between the hour
and the minute
hand.
Answers within 10-5
of the actual value will be accepted as correct.
Example 1:
Input: hour = 12, minutes = 30
Output: 165
Example 2:
Input: hour = 3, minutes = 30
Output: 75
Example 3:
Input: hour = 3, minutes = 15
Output: 7.5
Constraints:
-
1 <= hour <= 12
-
0 <= minutes <= 59
SOLUTION:
class Solution:
def angleClock(self, hour: int, minutes: int) -> float:
mAngle = minutes * 6
hAngle = (hour * 30 + minutes / 2) % 360
diff = abs(mAngle - hAngle)
return min(diff, 360 - diff)
Top comments (0)