You are given a string s
of even length. Split this string into two halves of equal lengths, and let a
be the first half and b
be the second half.
Two strings are alike if they have the same number of vowels ('a'
, 'e'
, 'i'
, 'o'
, 'u'
, 'A'
, 'E'
, 'I'
, 'O'
, 'U'
). Notice that s
contains uppercase and lowercase letters.
Return true
if a
and b
are alike. Otherwise, return false
.
Example 1:
Input: s = "book"
Output: true
Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.
Example 2:
Input: s = "textbook"
Output: false
Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike.
Notice that the vowel o is counted twice.
Constraints:
-
2 <= s.length <= 1000
-
s.length
is even. -
s
consists of uppercase and lowercase letters.
SOLUTION:
class Solution:
def halvesAreAlike(self, s: str) -> bool:
n = len(s)
vowels = {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}
f = len([i for i in range(n // 2) if s[i] in vowels])
s = len([i for i in range(n // 2, n) if s[i] in vowels])
return f == s
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