Given two string arrays word1
and word2
, return true
if the two arrays represent the same string, and false
otherwise.
A string is represented by an array if the array elements concatenated in order forms the string.
Example 1:
Input: word1 = ["ab", "c"], word2 = ["a", "bc"]
Output: true
Explanation:
word1 represents string "ab" + "c" -> "abc"
word2 represents string "a" + "bc" -> "abc"
The strings are the same, so return true.
Example 2:
Input: word1 = ["a", "cb"], word2 = ["ab", "c"]
Output: false
Example 3:
Input: word1 = ["abc", "d", "defg"], word2 = ["abcddefg"]
Output: true
Constraints:
-
1 <= word1.length, word2.length <= 103
-
1 <= word1[i].length, word2[i].length <= 103
-
1 <= sum(word1[i].length), sum(word2[i].length) <= 103
-
word1[i]
andword2[i]
consist of lowercase letters.
SOLUTION:
class Solution:
def arrayStringsAreEqual(self, word1: List[str], word2: List[str]) -> bool:
m = len(word1)
n = len(word2)
a, b = 0, 0
c, d = 0, 0
while a < m and c < n:
if word1[a][b] != word2[c][d]:
return False
a, b = a + (b + 1) // len(word1[a]), (b + 1) % len(word1[a])
c, d = c + (d + 1) // len(word2[c]), (d + 1) % len(word2[c])
return a >= m and c >= n
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