Given a string queryIP
, return "IPv4"
if IP is a valid IPv4 address, "IPv6"
if IP is a valid IPv6 address or "Neither"
if IP is not a correct IP of any type.
A valid IPv4 address is an IP in the form "x1.x2.x3.x4"
where 0 <= xi <= 255
and xi
cannot contain leading zeros. For example, "192.168.1.1"
and "192.168.1.0"
are valid IPv4 addresses while "192.168.01.1"
, "192.168.1.00"
, and "192.168@1.1"
are invalid IPv4 addresses.
A valid IPv6 address is an IP in the form "x1:x2:x3:x4:x5:x6:x7:x8"
where:
-
1 <= xi.length <= 4
-
xi
is a hexadecimal string which may contain digits, lowercase English letter ('a'
to'f'
) and upper-case English letters ('A'
to'F'
). - Leading zeros are allowed in
xi
.
For example, "2001:0db8:85a3:0000:0000:8a2e:0370:7334"
and "2001:db8:85a3:0:0:8A2E:0370:7334"
are valid IPv6 addresses, while "2001:0db8:85a3::8A2E:037j:7334"
and "02001:0db8:85a3:0000:0000:8a2e:0370:7334"
are invalid IPv6 addresses.
Example 1:
Input: queryIP = "172.16.254.1"
Output: "IPv4"
Explanation: This is a valid IPv4 address, return "IPv4".
Example 2:
Input: queryIP = "2001:0db8:85a3:0:0:8A2E:0370:7334"
Output: "IPv6"
Explanation: This is a valid IPv6 address, return "IPv6".
Example 3:
Input: queryIP = "256.256.256.256"
Output: "Neither"
Explanation: This is neither a IPv4 address nor a IPv6 address.
Constraints:
-
queryIP
consists only of English letters, digits and the characters'.'
and':'
.
SOLUTION:
class Solution:
def validIPAddress(self, queryIP: str) -> str:
isv4 = True
isv6 = True
if "." in queryIP:
isv6 = False
queryIP = queryIP.split(".")
if len(queryIP) != 4:
isv4 = False
else:
isv4 = False
if ":" in queryIP:
isv4 = False
queryIP = queryIP.split(":")
if len(queryIP) != 8:
isv6 = False
else:
isv6 = False
if isv4:
for x in queryIP:
if not x.isnumeric() or (len(x) > 1 and x[0] == "0") or not 0 <= int(x) < 256:
isv4 = False
break
if isv6:
for x in queryIP:
try:
int(x, 16)
if len(x) > 4:
raise
except:
isv6 = False
break
if isv4:
return "IPv4"
if isv6:
return "IPv6"
return "Neither"
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