Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly duration
seconds. More formally, an attack at second t
will mean Ashe is poisoned during the inclusive time interval [t, t + duration - 1]
. If Teemo attacks again before the poison effect ends, the timer for it is reset, and the poison effect will end duration
seconds after the new attack.
You are given a non-decreasing integer array timeSeries
, where timeSeries[i]
denotes that Teemo attacks Ashe at second timeSeries[i]
, and an integer duration
.
Return the total number of seconds that Ashe is poisoned.
Example 1:
Input: timeSeries = [1,4], duration = 2
Output: 4
Explanation: Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5. Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total.
Example 2:
Input: timeSeries = [1,2], duration = 2
Output: 3
Explanation: Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3. Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total.
Constraints:
-
1 <= timeSeries.length <= 104
-
0 <= timeSeries[i], duration <= 107
-
timeSeries
is sorted in non-decreasing order.
SOLUTION:
class Solution:
def findPoisonedDuration(self, timeSeries: List[int], duration: int) -> int:
n = len(timeSeries)
total = duration
for i in range(1, n):
total += min(timeSeries[i] - timeSeries[i - 1], duration)
return total
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