Given an integer n
, return true
if it is a power of three. Otherwise, return false
.
An integer n
is a power of three, if there exists an integer x
such that n == 3x
.
Example 1:
Input: n = 27
Output: true
Example 2:
Input: n = 0
Output: false
Example 3:
Input: n = 9
Output: true
Constraints:
-
-231 <= n <= 231 - 1
Follow up: Could you solve it without loops/recursion?SOLUTION:
class Solution:
def isPowerOfThree(self, n: int) -> bool:
if n <= 0:
return False
while n % 3 == 0:
n = n // 3
return n == 1
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