Implement the class SubrectangleQueries
which receives a rows x cols
rectangle as a matrix of integers in the constructor and supports two methods:
1. updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)
- Updates all values with
newValue
in the subrectangle whose upper left coordinate is(row1,col1)
and bottom right coordinate is(row2,col2)
.
2. getValue(int row, int col)
- Returns the current value of the coordinate
(row,col)
from the rectangle.
Example 1:
Input
["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue","getValue"]
[[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]
Output
[null,1,null,5,5,null,10,5]
Explanation
SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]);
// The initial rectangle (4x3) looks like:
// 1 2 1
// 4 3 4
// 3 2 1
// 1 1 1
subrectangleQueries.getValue(0, 2); // return 1
subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5);
// After this update the rectangle looks like:
// 5 5 5
// 5 5 5
// 5 5 5
// 5 5 5
subrectangleQueries.getValue(0, 2); // return 5
subrectangleQueries.getValue(3, 1); // return 5
subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10);
// After this update the rectangle looks like:
// 5 5 5
// 5 5 5
// 5 5 5
// 10 10 10
subrectangleQueries.getValue(3, 1); // return 10
subrectangleQueries.getValue(0, 2); // return 5
Example 2:
Input
["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue"]
[[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]
Output
[null,1,null,100,100,null,20]
Explanation
SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]);
subrectangleQueries.getValue(0, 0); // return 1
subrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100);
subrectangleQueries.getValue(0, 0); // return 100
subrectangleQueries.getValue(2, 2); // return 100
subrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20);
subrectangleQueries.getValue(2, 2); // return 20
Constraints:
- There will be at most
500
operations considering both methods:updateSubrectangle
andgetValue
. -
1 <= rows, cols <= 100
-
rows == rectangle.length
-
cols == rectangle[i].length
-
0 <= row1 <= row2 < rows
-
0 <= col1 <= col2 < cols
-
1 <= newValue, rectangle[i][j] <= 10^9
-
0 <= row < rows
-
0 <= col < cols
SOLUTION:
class SubrectangleQueries:
def __init__(self, rectangle: List[List[int]]):
self.rec = rectangle
def updateSubrectangle(self, row1: int, col1: int, row2: int, col2: int, newValue: int) -> None:
for i in range(row1, row2 + 1):
for j in range(col1, col2 + 1):
self.rec[i][j] = newValue
def getValue(self, row: int, col: int) -> int:
return self.rec[row][col]
# Your SubrectangleQueries object will be instantiated and called as such:
# obj = SubrectangleQueries(rectangle)
# obj.updateSubrectangle(row1,col1,row2,col2,newValue)
# param_2 = obj.getValue(row,col)
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