Given a string path
, which is an absolute path (starting with a slash '/'
) to a file or directory in a Unix-style file system, convert it to the simplified canonical path.
In a Unix-style file system, a period '.'
refers to the current directory, a double period '..'
refers to the directory up a level, and any multiple consecutive slashes (i.e. '//'
) are treated as a single slash '/'
. For this problem, any other format of periods such as '...'
are treated as file/directory names.
The canonical path should have the following format:
- The path starts with a single slash
'/'
. - Any two directories are separated by a single slash
'/'
. - The path does not end with a trailing
'/'
. - The path only contains the directories on the path from the root directory to the target file or directory (i.e., no period
'.'
or double period'..'
)
Return the simplified canonical path.
Example 1:
Input: path = "/home/"
Output: "/home"
Explanation: Note that there is no trailing slash after the last directory name.
Example 2:
Input: path = "/../"
Output: "/"
Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.
Example 3:
Input: path = "/home//foo/"
Output: "/home/foo"
Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.
Constraints:
-
1 <= path.length <= 3000
-
path
consists of English letters, digits, period'.'
, slash'/'
or'_'
. -
path
is a valid absolute Unix path.
SOLUTION:
class Solution:
def simplifyPath(self, path: str) -> str:
path += "/"
chunk = ""
chunks = []
for c in path:
if c == "/":
if len(chunk) > 0:
chunks.append(chunk)
chunk = ""
else:
chunk += c
curr = []
for folder in chunks:
if folder == "..":
if len(curr) > 0:
curr.pop()
elif folder != ".":
curr.append(folder)
return "/" + "/".join(curr)
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