Given a string s
and a character letter
, return the percentage of characters in s
that equal letter
rounded down to the nearest whole percent.
Example 1:
Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.
Example 2:
Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.
Constraints:
-
1 <= s.length <= 100
-
s
consists of lowercase English letters. -
letter
is a lowercase English letter.
SOLUTION:
class Solution:
def percentageLetter(self, s: str, letter: str) -> int:
n = len(s)
ctr = 0
for c in s:
if c == letter:
ctr += 1
return floor(100 * ctr / n)
Top comments (1)
Why not use str.count method?