There is a programming language with only four operations and one variable X
:
-
++X
andX++
increments the value of the variableX
by1
. -
--X
andX--
decrements the value of the variableX
by1
.
Initially, the value of X
is 0
.
Given an array of strings operations
containing a list of operations, return the final value of X
after performing all the operations.
Example 1:
Input: operations = ["--X","X++","X++"]
Output: 1
Explanation: The operations are performed as follows:
Initially, X = 0.
--X: X is decremented by 1, X = 0 - 1 = -1.
X++: X is incremented by 1, X = -1 + 1 = 0.
X++: X is incremented by 1, X = 0 + 1 = 1.
Example 2:
Input: operations = ["++X","++X","X++"]
Output: 3
Explanation: The operations are performed as follows:
Initially, X = 0.
++X: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
X++: X is incremented by 1, X = 2 + 1 = 3.
Example 3:
Input: operations = ["X++","++X","--X","X--"]
Output: 0
Explanation: The operations are performed as follows:
Initially, X = 0.
X++: X is incremented by 1, X = 0 + 1 = 1.
++X: X is incremented by 1, X = 1 + 1 = 2.
--X: X is decremented by 1, X = 2 - 1 = 1.
X--: X is decremented by 1, X = 1 - 1 = 0.
Constraints:
-
1 <= operations.length <= 100
-
operations[i]
will be either"++X"
,"X++"
,"--X"
, or"X--"
.
SOLUTION:
class Solution:
def finalValueAfterOperations(self, operations: List[str]) -> int:
x = 0
for o in operations:
if o[1] == '+':
x += 1
if o[1] == '-':
x -= 1
return x
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