Given a 0-indexed integer array nums
of size n
, find the maximum difference between nums[i]
and nums[j]
(i.e., nums[j] - nums[i]
), such that 0 <= i < j < n
and nums[i] < nums[j]
.
Return the maximum difference. If no such i
and j
exists, return -1
.
Example 1:
Input: nums = [7,1,5,4]
Output: 4
Explanation:
The maximum difference occurs with i = 1 and j = 2, nums[j] - nums[i] = 5 - 1 = 4.
Note that with i = 1 and j = 0, the difference nums[j] - nums[i] = 7 - 1 = 6, but i > j, so it is not valid.
Example 2:
Input: nums = [9,4,3,2]
Output: -1
Explanation:
There is no i and j such that i < j and nums[i] < nums[j].
Example 3:
Input: nums = [1,5,2,10]
Output: 9
Explanation:
The maximum difference occurs with i = 0 and j = 3, nums[j] - nums[i] = 10 - 1 = 9.
Constraints:
-
n == nums.length
-
2 <= n <= 1000
-
1 <= nums[i] <= 109
SOLUTION:
class Solution:
def maximumDifference(self, nums: List[int]) -> int:
mdiff = float('-inf')
minSoFar = nums[0]
for num in nums:
minSoFar = min(minSoFar, num)
mdiff = max(mdiff, num - minSoFar)
if mdiff > 0:
return mdiff
return -1
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