Given an integer number n
, return the difference between the product of its digits and the sum of its digits.
Example 1:
Input: n = 234
Output: 15
Explanation:
Product of digits = 2 * 3 * 4 = 24
Sum of digits = 2 + 3 + 4 = 9
Result = 24 - 9 = 15
Example 2:
Input: n = 4421
Output: 21
Explanation:
Product of digits = 4 * 4 * 2 * 1 = 32
Sum of digits = 4 + 4 + 2 + 1 = 11
Result = 32 - 11 = 21
Constraints:
-
1 <= n <= 10^5
SOLUTION:
class Solution:
def subtractProductAndSum(self, n: int) -> int:
p = 1
s = 0
while n > 0:
d = n % 10
p *= d
s += d
n = n // 10
return p - s
Top comments (0)