Given a non-negative integer x
, compute and return the square root of x
.
Since the return type is an integer, the decimal digits are truncated, and only the integer part of the result is returned.
Note: You are not allowed to use any built-in exponent function or operator, such as pow(x, 0.5)
or x ** 0.5
.
Example 1:
Input: x = 4
Output: 2
Example 2:
Input: x = 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.
Constraints:
-
0 <= x <= 231 - 1
SOLUTION:
class Solution:
def mySqrt(self, x: int) -> int:
beg = 0
end = x
while beg <= end:
mid = (beg + end) // 2
if mid * mid <= x and (mid + 1) * (mid + 1) > x:
return mid
elif mid * mid > x:
end = mid
else:
beg = mid + 1
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