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Abhishek Chaudhary
Abhishek Chaudhary

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Fizz Buzz

Given an integer n, return a string array answer (1-indexed) where:

  • answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
  • answer[i] == "Fizz" if i is divisible by 3.
  • answer[i] == "Buzz" if i is divisible by 5.
  • answer[i] == i (as a string) if none of the above conditions are true.

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Constraints:

  • 1 <= n <= 104

SOLUTION:

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        return [[str(i), "Fizz", "Buzz", "FizzBuzz"][2 * int(i % 5 == 0) + int(i % 3 == 0)] for i in range(1, n + 1)]
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