There are n
kids with candies. You are given an integer array candies
, where each candies[i]
represents the number of candies the ith
kid has, and an integer extraCandies
, denoting the number of extra candies that you have.
Return a boolean array result
of length n
, where result[i]
is true
if, after giving the ith
kid all the extraCandies
, they will have the greatest number of candies among all the kids, or false
otherwise.
Note that multiple kids can have the greatest number of candies.
Example 1:
Input: candies = [2,3,5,1,3], extraCandies = 3
Output: [true,true,true,false,true]
Explanation: If you give all extraCandies to:
- Kid 1, they will have 2 + 3 = 5 candies, which is the greatest among the kids.
- Kid 2, they will have 3 + 3 = 6 candies, which is the greatest among the kids.
- Kid 3, they will have 5 + 3 = 8 candies, which is the greatest among the kids.
- Kid 4, they will have 1 + 3 = 4 candies, which is not the greatest among the kids.
- Kid 5, they will have 3 + 3 = 6 candies, which is the greatest among the kids.
Example 2:
Input: candies = [4,2,1,1,2], extraCandies = 1
Output: [true,false,false,false,false]
Explanation: There is only 1 extra candy.
Kid 1 will always have the greatest number of candies, even if a different kid is given the extra candy.
Example 3:
Input: candies = [12,1,12], extraCandies = 10
Output: [true,false,true]
Constraints:
-
n == candies.length
-
2 <= n <= 100
-
1 <= candies[i] <= 100
-
1 <= extraCandies <= 50
SOLUTION:
class Solution:
def kidsWithCandies(self, candies: List[int], extraCandies: int) -> List[bool]:
mx = max(candies)
return [c + extraCandies >= mx for c in candies]
Top comments (1)
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