You are given the heads of two sorted linked lists list1
and list2
.
Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.
Return the head of the merged linked list.
Example 1:
Input: list1 = [1,2,4], list2 = [1,3,4]
Output: [1,1,2,3,4,4]
Example 2:
Input: list1 = [], list2 = []
Output: []
Example 3:
Input: list1 = [], list2 = [0]
Output: [0]
Constraints:
- The number of nodes in both lists is in the range
[0, 50]
. -
-100 <= Node.val <= 100
- Both
list1
andlist2
are sorted in non-decreasing order.
SOLUTION:
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def mergeTwoLists(self, l1, l2):
if l1 and l2:
a, b = l1, l2
if b.val < a.val:
a, b = b, a
a.next = self.mergeTwoLists(a.next, b)
return a
return l1 or l2
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