A website domain "discuss.leetcode.com"
consists of various subdomains. At the top level, we have "com"
, at the next level, we have "leetcode.com"
and at the lowest level, "discuss.leetcode.com"
. When we visit a domain like "discuss.leetcode.com"
, we will also visit the parent domains "leetcode.com"
and "com"
implicitly.
A count-paired domain is a domain that has one of the two formats "rep d1.d2.d3"
or "rep d1.d2"
where rep
is the number of visits to the domain and d1.d2.d3
is the domain itself.
- For example,
"9001 discuss.leetcode.com"
is a count-paired domain that indicates thatdiscuss.leetcode.com
was visited9001
times.
Given an array of count-paired domains cpdomains
, return an array of the count-paired domains of each subdomain in the input. You may return the answer in any order.
Example 1:
Input: cpdomains = ["9001 discuss.leetcode.com"]
Output: ["9001 leetcode.com","9001 discuss.leetcode.com","9001 com"]
Explanation: We only have one website domain: "discuss.leetcode.com".
As discussed above, the subdomain "leetcode.com" and "com" will also be visited. So they will all be visited 9001 times.
Example 2:
Input: cpdomains = ["900 google.mail.com", "50 yahoo.com", "1 intel.mail.com", "5 wiki.org"]
Output: ["901 mail.com","50 yahoo.com","900 google.mail.com","5 wiki.org","5 org","1 intel.mail.com","951 com"]
Explanation: We will visit "google.mail.com" 900 times, "yahoo.com" 50 times, "intel.mail.com" once and "wiki.org" 5 times.
For the subdomains, we will visit "mail.com" 900 + 1 = 901 times, "com" 900 + 50 + 1 = 951 times, and "org" 5 times.
Constraints:
-
1 <= cpdomain.length <= 100
-
1 <= cpdomain[i].length <= 100
-
cpdomain[i]
follows either the"repi d1i.d2i.d3i"
format or the"repi d1i.d2i"
format. -
repi
is an integer in the range[1, 104]
. -
d1i
,d2i
, andd3i
consist of lowercase English letters.
SOLUTION:
class Solution:
def subdomainVisits(self, cpdomains: List[str]) -> List[str]:
ctr = {}
for val in cpdomains:
rep, domain = val.split(" ")
rep = int(rep)
doms = domain.split(".")
n = len(doms)
for i in range(n):
curr = ".".join(doms[i:])
ctr[curr] = ctr.get(curr, 0) + rep
return ["{} {}".format(v, k) for k, v in ctr.items()]
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