Given two strings word1
and word2
, return the minimum number of steps required to make word1
and word2
the same.
In one step, you can delete exactly one character in either string.
Example 1:
Input: word1 = "sea", word2 = "eat"
Output: 2
Explanation: You need one step to make "sea" to "ea" and another step to make "eat" to "ea".
Example 2:
Input: word1 = "leetcode", word2 = "etco"
Output: 4
Constraints:
-
1 <= word1.length, word2.length <= 500
-
word1
andword2
consist of only lowercase English letters.
SOLUTION:
class Solution:
def md(self, word1, word2, i1, i2):
if (i1, i2) in self.cache:
return self.cache[(i1, i2)]
if i1 == len(word1):
return len(word2) - i2
if i2 == len(word2):
return len(word1) - i1
if word1[i1] == word2[i2]:
self.cache[(i1, i2)] = min(self.md(word1, word2, i1 + 1, i2 + 1), 1 + self.md(word1, word2, i1, i2 + 1), 1 + self.md(word1, word2, i1 + 1, i2))
return self.cache[(i1, i2)]
else:
self.cache[(i1, i2)] = 1 + min(self.md(word1, word2, i1, i2 + 1), self.md(word1, word2, i1 + 1, i2))
return self.cache[(i1, i2)]
def minDistance(self, word1: str, word2: str) -> int:
self.cache = {}
return self.md(word1, word2, 0, 0)
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