Given an array of strings words
representing an English Dictionary, return the longest word in words
that can be built one character at a time by other words in words
.
If there is more than one possible answer, return the longest word with the smallest lexicographical order. If there is no answer, return the empty string.
Example 1:
Input: words = ["w","wo","wor","worl","world"]
Output: "world"
Explanation: The word "world" can be built one character at a time by "w", "wo", "wor", and "worl".
Example 2:
Input: words = ["a","banana","app","appl","ap","apply","apple"]
Output: "apple"
Explanation: Both "apply" and "apple" can be built from other words in the dictionary. However, "apple" is lexicographically smaller than "apply".
Constraints:
-
1 <= words.length <= 1000
-
1 <= words[i].length <= 30
-
words[i]
consists of lowercase English letters.
SOLUTION:
class Solution:
def longestWord(self, words: List[str]) -> str:
words = set(words)
mword = ""
for word in words:
n = len(word)
valid = True
for i in range(1, n):
if word[:i] not in words:
valid = False
break
if valid:
if len(word) > len(mword):
mword = word
elif len(word) == len(mword) and word < mword:
mword = word
return mword
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