You're given strings jewels
representing the types of stones that are jewels, and stones
representing the stones you have. Each character in stones
is a type of stone you have. You want to know how many of the stones you have are also jewels.
Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
Example 1:
Input: jewels = "aA", stones = "aAAbbbb"
Output: 3
Example 2:
Input: jewels = "z", stones = "ZZ"
Output: 0
Constraints:
-
1 <= jewels.length, stones.length <= 50
-
jewels
andstones
consist of only English letters. - All the characters of
jewels
are unique.
SOLUTION:
class Solution:
def numJewelsInStones(self, jewels: str, stones: str) -> int:
jewels = set(jewels)
return len([c for c in stones if c in jewels])
Top comments (1)
Une Ligne Paris has spent over forty years crafting a unique presence in the world of fashion jewelry. Known for its innovative designs and attention to detail, the brand consistently sets itself apart. Its timeless creations blend classic elegance with contemporary flair. uneligne.ch/ legacy of excellence continues to resonate in the fashion industry today.